Instructor’s Solutions Manual of College Algebra And by Richard N. Aufmann

By Richard N. Aufmann

Comprises whole strategies to all odd-numbered difficulties within the textual content, in addition to learn assistance and a convention checks for every bankruptcy; textual content particular.

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All rights reserved. 2 41 11. 8 12. 5 13. 5 17. 14. Let x = the number 1 1 1 x + x = x −5 5 4 2 1 ⎞ ⎛1 ⎛1 ⎞ 20⎜ x + x ⎟ = 20⎜ x − 5 ⎟ 5 4 2 ⎝ ⎠ ⎝ ⎠ 4 x + 5 x = 10 x − 100 9 x = 10 x − 100 100 = x 15. 2 18. 1) The original fraction is x−4 . 2 W P = 2 L + 2W 174 = 2(2W − 3) + 2W 174 = 4W − 6 + 2W 180 = 6W W = 30 ft L = 2W − 3 = 2(30) − 3 = 60 − 3 = 57 ft x + 10 = 5 x − 50 − 4 x = −60 The original fraction is 15 − 4 11 = . 15 15 21. 22. 110 = 2 L + 2 ⎡ 1 L + 1⎤ ⎣2 ⎦ 110 = 2 L + L + 2 108 = 3L L = 36 m W = 1 L + 1 = 1 (36) + 1 2 3x + 3 x + x = 84 7 x = 84 x = 12 3 x = 3(12) = 36 The shortest side is 12 cm.

X+2=0 x = −24 or x −1 = 0 x =1 12 x 2 − 41x + 24 = 0 (4 x − 3)(3x −8) = 0 4 x −3 = 0 or 3 x −8 = 0 4x = 3 3x = 8 3 x= x=8 4 3 Copyright © Houghton Mifflin Company. All rights reserved. 3 7. 49 3x 2 − 7 x = 0 x (3 x − 7 ) = 0 x = 0 or 3 x − 7 = 0 3x = 7 7 x= 3 8. 13. 11. 2 x 2 = 48 14. x=8 x 2 = 81 12. x=2 x 2 = 225 x = ± 225 x = ± 15 3x 2 = 144 15. 3x 2 + 12 = 0 3x 2 = −12 x 2 = −4 x 2 = 48 x = ± 24 x = ± 48 x = ±2 6 x = ±4 3 4 x 2 + 20 = 0 17. x = ± −4 x = ± 2i ( x − 5)2 = 36 18. x − 5 = ± 36 x − 5 = ±6 x = 5±6 x = 5 + 6 or x = 5−6 x = 11 x = −1 2 x = −5 x = ± −5 x = ±i 5 ( x − 3) 2 + 16 = 0 20.

Let 160 – t = the time in seconds to jog back. 6t = 2(160 − t ) 6t = 320 − 2t 8t = 320 t = 40 d = 6(40) = 240 meters Let t = the time (in hours) to travel to the island. 5 – t = the time (in hours) to return. 5 − t ) 15t = 75 − 10t 25t = 75 t = 3 hours d = 15(3) = 45 nautical miles 25. 26. d = 240(t + 3) Let t = time (in hours) of the first plane. Let t – 1 = time (in hours) of the second plane. d = 600t Let t = the time (in hours) of the second plane. Let t + 3 = the time (in hours) of the first plane.

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