# Complex analysis by Douglas Arnold By Douglas Arnold

Lecture notes.

Read Online or Download Complex analysis PDF

Similar analysis books

Multidisciplinary Methods for Analysis Optimization and Control of Complex Systems

This booklet includes lecture notes of a summer season institution named after the past due Jacques Louis Lions. The summer time institution used to be designed to alert either Academia and to the expanding function of multidisciplinary equipment and instruments for the layout of advanced items in quite a few parts of socio-economic curiosity.

Additional resources for Complex analysis

Example text

The difference between this function and u satisfies the mean value property and is zero on the boundary of the disk, so it vanishes on the disk. Corollary. If a sequence of harmonic functions converges uniformly on compact subsets, then the limit function is harmonic. From the expressions Pr (θ) = we have 1 − r2 1 − r2 = (1 + r)2 − 2r(1 + cos θ) (1 − r)2 + 2r(1 − cos θ) 1−r 1+r ≤ Pr (θ) ≤ . 1+r 1−r Now suppose u is harmonic on B(0, R) and non-negative, and reiθ is an arbitrary point of B(0, R).

Let G, G+ , G− , and G0 be as above. If f is a continuous complex-valued function on G+ ∪ G0 , which is analytic on G+ and real on G0 , then f admits a unique extension to a harmonic function on all of G. The extension is given by f (z) = f (¯ z ) for z ∈ G− . Proof. We could base a proof on the previous result applied to Im f and harmonic conjugates, but it is also easy to verify this directly using Morera’s theorem. 39 Of course the line of symmetry could be any line, not just the real axis. Thus if G is symmetric with respect to any line, defined and analytic on one side of the line, and real on the line, it can be extended to be analytic on the whole domain.

Proof. If such an extension exists it is certainly unique, so it suffices to show that the stated extension defines a harmonic function in G. It certainly defines a continuous extension which is harmonic in G+ ∪ G− , so it suffices to show that it is harmonic in a neighborhood of z0 ∈ G0 . By translating and extending we can assume that z0 = 0 and that G contains ¯ Define U on D ¯ as the solution of the Dirichlet problem with the closed unit disk, D. boundary data u|∂D (where u has been extended to G− by the formula above).

Download PDF sample

Rated 4.84 of 5 – based on 35 votes